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133252013412233 is a prime number
BaseRepresentation
bin11110010011000100100110…
…111011001100111110001001
3122110210202201220222100200122
4132103010212323030332021
5114431200110413142413
61151223044015313025
740032066053501042
oct3623044673147611
9573722656870618
10133252013412233
1139504952775601
1212b4117181b775
1359477c3336051
1424c96090538c9
1510612cd768108
hex793126eccf89

133252013412233 has 2 divisors, whose sum is σ = 133252013412234. Its totient is φ = 133252013412232.

The previous prime is 133252013412187. The next prime is 133252013412247. The reversal of 133252013412233 is 332214310252331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 118063284370249 + 15188729041984 = 10865693^2 + 3897272^2 .

It is a cyclic number.

It is not a de Polignac number, because 133252013412233 - 26 = 133252013412169 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 133252013412193 and 133252013412202.

It is not a weakly prime, because it can be changed into another prime (133252013472233) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66626006706116 + 66626006706117.

It is an arithmetic number, because the mean of its divisors is an integer number (66626006706117).

Almost surely, 2133252013412233 is an apocalyptic number.

It is an amenable number.

133252013412233 is a deficient number, since it is larger than the sum of its proper divisors (1).

133252013412233 is an equidigital number, since it uses as much as digits as its factorization.

133252013412233 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 77760, while the sum is 35.

Adding to 133252013412233 its reverse (332214310252331), we get a palindrome (465466323664564).

The spelling of 133252013412233 in words is "one hundred thirty-three trillion, two hundred fifty-two billion, thirteen million, four hundred twelve thousand, two hundred thirty-three".