Base | Representation |
---|---|
bin | 111110000011001110… |
… | …1101110000100100001 |
3 | 110201221120222100000122 |
4 | 1330012131232010201 |
5 | 4140400111042403 |
6 | 141114302130025 |
7 | 12425056024514 |
oct | 1740635560441 |
9 | 421846870018 |
10 | 133252440353 |
11 | 5156a58a76a |
12 | 219a9b80915 |
13 | c747974456 |
14 | 6641424d7b |
15 | 36ed66e838 |
hex | 1f0676e121 |
133252440353 has 2 divisors, whose sum is σ = 133252440354. Its totient is φ = 133252440352.
The previous prime is 133252440341. The next prime is 133252440371. The reversal of 133252440353 is 353044252331.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 120670780129 + 12581660224 = 347377^2 + 112168^2 .
It is an emirp because it is prime and its reverse (353044252331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 133252440353 - 212 = 133252436257 is a prime.
It is not a weakly prime, because it can be changed into another prime (133252440653) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66626220176 + 66626220177.
It is an arithmetic number, because the mean of its divisors is an integer number (66626220177).
Almost surely, 2133252440353 is an apocalyptic number.
It is an amenable number.
133252440353 is a deficient number, since it is larger than the sum of its proper divisors (1).
133252440353 is an equidigital number, since it uses as much as digits as its factorization.
133252440353 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 129600, while the sum is 35.
Adding to 133252440353 its reverse (353044252331), we get a palindrome (486296692684).
The spelling of 133252440353 in words is "one hundred thirty-three billion, two hundred fifty-two million, four hundred forty thousand, three hundred fifty-three".
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