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13325434644419 is a prime number
BaseRepresentation
bin1100000111101001000111…
…0011000110011111000011
31202011220021110012100212222
43001322101303012133003
53221310442232110134
644201341542241255
72543505456421232
oct301722163063703
952156243170788
1013325434644419
114278315510887
1215b268512622b
137587770a1a81
14340d51132b19
15181959c71a2e
hexc1e91cc67c3

13325434644419 has 2 divisors, whose sum is σ = 13325434644420. Its totient is φ = 13325434644418.

The previous prime is 13325434644413. The next prime is 13325434644499. The reversal of 13325434644419 is 91444643452331.

13325434644419 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13325434644419 is a prime.

It is a super-2 number, since 2×133254346444192 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13325434644413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6662717322209 + 6662717322210.

It is an arithmetic number, because the mean of its divisors is an integer number (6662717322210).

Almost surely, 213325434644419 is an apocalyptic number.

13325434644419 is a deficient number, since it is larger than the sum of its proper divisors (1).

13325434644419 is an equidigital number, since it uses as much as digits as its factorization.

13325434644419 is an evil number, because the sum of its binary digits is even.

The product of its digits is 14929920, while the sum is 53.

The spelling of 13325434644419 in words is "thirteen trillion, three hundred twenty-five billion, four hundred thirty-four million, six hundred forty-four thousand, four hundred nineteen".