Base | Representation |
---|---|
bin | 111110000011010111… |
… | …1111001010000011011 |
3 | 110201221220221101120021 |
4 | 1330012233321100123 |
5 | 4140402321023023 |
6 | 141114552211311 |
7 | 12425144360104 |
oct | 1740657712033 |
9 | 421856841507 |
10 | 133257204763 |
11 | 515722442a1 |
12 | 219ab699b37 |
13 | c748951c27 |
14 | 6641d053ab |
15 | 36edcb135d |
hex | 1f06bf941b |
133257204763 has 4 divisors (see below), whose sum is σ = 133267326208. Its totient is φ = 133247083320.
The previous prime is 133257204757. The next prime is 133257204797. The reversal of 133257204763 is 367402752331.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 367402752331 = 56269 ⋅6529399.
It is a cyclic number.
It is not a de Polignac number, because 133257204763 - 213 = 133257196571 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (133257204713) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5040948 + ... + 5067313.
It is an arithmetic number, because the mean of its divisors is an integer number (33316831552).
Almost surely, 2133257204763 is an apocalyptic number.
133257204763 is a deficient number, since it is larger than the sum of its proper divisors (10121445).
133257204763 is a wasteful number, since it uses less digits than its factorization.
133257204763 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10121444.
The product of its (nonzero) digits is 635040, while the sum is 43.
The spelling of 133257204763 in words is "one hundred thirty-three billion, two hundred fifty-seven million, two hundred four thousand, seven hundred sixty-three".
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