Search a number
-
+
133300112022937 is a prime number
BaseRepresentation
bin11110010011110001011001…
…110100110101110110011001
3122110222100212222222221112201
4132103301121310311312121
5114432442112134213222
61151301120455410201
740035421020106546
oct3623613164656631
9573870788887481
10133300112022937
1139523295123742
1212b4a555983961
13594c1ba1a6a42
1424cba8d037bcd
151062696228427
hex793c59d35d99

133300112022937 has 2 divisors, whose sum is σ = 133300112022938. Its totient is φ = 133300112022936.

The previous prime is 133300112022919. The next prime is 133300112023033. The reversal of 133300112022937 is 739220211003331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 99506689892416 + 33793422130521 = 9975304^2 + 5813211^2 .

It is an emirp because it is prime and its reverse (739220211003331) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-133300112022937 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 133300112022896 and 133300112022905.

It is not a weakly prime, because it can be changed into another prime (133300112022037) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66650056011468 + 66650056011469.

It is an arithmetic number, because the mean of its divisors is an integer number (66650056011469).

Almost surely, 2133300112022937 is an apocalyptic number.

It is an amenable number.

133300112022937 is a deficient number, since it is larger than the sum of its proper divisors (1).

133300112022937 is an equidigital number, since it uses as much as digits as its factorization.

133300112022937 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 40824, while the sum is 37.

The spelling of 133300112022937 in words is "one hundred thirty-three trillion, three hundred billion, one hundred twelve million, twenty-two thousand, nine hundred thirty-seven".