Base | Representation |
---|---|
bin | 1100000111111010001110… |
… | …1110010000100110100011 |
3 | 1202012100010201210111112002 |
4 | 3001332203232100212203 |
5 | 3221344400231113243 |
6 | 44203421551554215 |
7 | 2544030402214235 |
oct | 301764356204643 |
9 | 52170121714462 |
10 | 13330030332323 |
11 | 427a263678161 |
12 | 15b354822b96b |
13 | 75902a23c423 |
14 | 34126962a255 |
15 | 181b28461eb8 |
hex | c1fa3b909a3 |
13330030332323 has 4 divisors (see below), whose sum is σ = 13555963049880. Its totient is φ = 13104097614768.
The previous prime is 13330030332293. The next prime is 13330030332383. The reversal of 13330030332323 is 32323303003331.
13330030332323 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13330030332323 - 232 = 13325735365027 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13330030332383) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 112966358690 + ... + 112966358807.
It is an arithmetic number, because the mean of its divisors is an integer number (3388990762470).
Almost surely, 213330030332323 is an apocalyptic number.
13330030332323 is a deficient number, since it is larger than the sum of its proper divisors (225932717557).
13330030332323 is an equidigital number, since it uses as much as digits as its factorization.
13330030332323 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 225932717556.
The product of its (nonzero) digits is 26244, while the sum is 29.
Adding to 13330030332323 its reverse (32323303003331), we get a palindrome (45653333335654).
The spelling of 13330030332323 in words is "thirteen trillion, three hundred thirty billion, thirty million, three hundred thirty-two thousand, three hundred twenty-three".
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