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133301003033131 is a prime number
BaseRepresentation
bin11110010011110010001110…
…111011110001101000101011
3122110222110012002120221202021
4132103302032323301220223
5114433000423234030011
61151301345125045311
740035452056424113
oct3623621673615053
9573873162527667
10133301003033131
11395237020758aa
1212b4a764256837
13594c2cc9735cb
1424cbb354d4043
1510626e957b471
hex793c8eef1a2b

133301003033131 has 2 divisors, whose sum is σ = 133301003033132. Its totient is φ = 133301003033130.

The previous prime is 133301003033069. The next prime is 133301003033137. The reversal of 133301003033131 is 131330300103331.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 133301003033131 - 223 = 133300994644523 is a prime.

It is a super-2 number, since 2×1333010030331312 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 133301003033096 and 133301003033105.

It is not a weakly prime, because it can be changed into another prime (133301003033137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66650501516565 + 66650501516566.

It is an arithmetic number, because the mean of its divisors is an integer number (66650501516566).

Almost surely, 2133301003033131 is an apocalyptic number.

133301003033131 is a deficient number, since it is larger than the sum of its proper divisors (1).

133301003033131 is an equidigital number, since it uses as much as digits as its factorization.

133301003033131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2187, while the sum is 25.

Adding to 133301003033131 its reverse (131330300103331), we get a palindrome (264631303136462).

The spelling of 133301003033131 in words is "one hundred thirty-three trillion, three hundred one billion, three million, thirty-three thousand, one hundred thirty-one".