Base | Representation |
---|---|
bin | 10011011001011101101… |
… | …001111000000000000011 |
3 | 11201102201211121002220002 |
4 | 103121131221320000003 |
5 | 133320001321321011 |
6 | 2500213222310215 |
7 | 165210154366205 |
oct | 23313551700003 |
9 | 4642654532802 |
10 | 1333011120131 |
11 | 474366031359 |
12 | 19641a88836b |
13 | 98919268412 |
14 | 48737892775 |
15 | 24a1c08cc3b |
hex | 1365da78003 |
1333011120131 has 2 divisors, whose sum is σ = 1333011120132. Its totient is φ = 1333011120130.
The previous prime is 1333011120121. The next prime is 1333011120137. The reversal of 1333011120131 is 1310211103331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1333011120131 - 214 = 1333011103747 is a prime.
It is a super-2 number, since 2×13330111201312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1333011120137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 666505560065 + 666505560066.
It is an arithmetic number, because the mean of its divisors is an integer number (666505560066).
Almost surely, 21333011120131 is an apocalyptic number.
1333011120131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1333011120131 is an equidigital number, since it uses as much as digits as its factorization.
1333011120131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 162, while the sum is 20.
Adding to 1333011120131 its reverse (1310211103331), we get a palindrome (2643222223462).
The spelling of 1333011120131 in words is "one trillion, three hundred thirty-three billion, eleven million, one hundred twenty thousand, one hundred thirty-one".
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