Search a number
-
+
133301201001 = 344433733667
BaseRepresentation
bin111110000100101011…
…1101110100001101001
3110202001222201122001120
41330021113232201221
54141000101413001
6141123203205453
712426220341033
oct1741127564151
9422058648046
10133301201001
1151595064321
1221a02376889
13c754ab76c7
146647ab8c53
153702aa2236
hex1f095ee869

133301201001 has 4 divisors (see below), whose sum is σ = 177734934672. Its totient is φ = 88867467332.

The previous prime is 133301200937. The next prime is 133301201003. The reversal of 133301201001 is 100102103331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 100102103331 = 333367367777.

It is a cyclic number.

It is not a de Polignac number, because 133301201001 - 26 = 133301200937 is a prime.

It is not an unprimeable number, because it can be changed into a prime (133301201003) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22216866831 + ... + 22216866836.

It is an arithmetic number, because the mean of its divisors is an integer number (44433733668).

Almost surely, 2133301201001 is an apocalyptic number.

It is an amenable number.

133301201001 is a deficient number, since it is larger than the sum of its proper divisors (44433733671).

133301201001 is an equidigital number, since it uses as much as digits as its factorization.

133301201001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 44433733670.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 133301201001 its reverse (100102103331), we get a palindrome (233403304332).

The spelling of 133301201001 in words is "one hundred thirty-three billion, three hundred one million, two hundred one thousand, one".

Divisors: 1 3 44433733667 133301201001