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13330121113 = 97137423929
BaseRepresentation
bin11000110101000100…
…11000000110011001
31021101222222022111101
430122202120012121
5204300002333423
610042422431401
7651222105601
oct143242300631
937358868441
1013330121113
115720562321
122700292561
1313458b793a
1490653dc01
155304107ad
hex31a898199

13330121113 has 4 divisors (see below), whose sum is σ = 13467545140. Its totient is φ = 13192697088.

The previous prime is 13330121111. The next prime is 13330121149. The reversal of 13330121113 is 31112103331.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 5887953289 + 7442167824 = 76733^2 + 86268^2 .

It is a cyclic number.

It is not a de Polignac number, because 13330121113 - 21 = 13330121111 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13330121111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 68711868 + ... + 68712061.

It is an arithmetic number, because the mean of its divisors is an integer number (3366886285).

Almost surely, 213330121113 is an apocalyptic number.

It is an amenable number.

13330121113 is a deficient number, since it is larger than the sum of its proper divisors (137424027).

13330121113 is an equidigital number, since it uses as much as digits as its factorization.

13330121113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 137424026.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 13330121113 its reverse (31112103331), we get a palindrome (44442224444).

The spelling of 13330121113 in words is "thirteen billion, three hundred thirty million, one hundred twenty-one thousand, one hundred thirteen".

Divisors: 1 97 137423929 13330121113