13330214005331 has 4 divisors (see below), whose sum is σ = 13387425224472. Its totient is φ = 13273002786192.

The previous prime is 13330214005291. The next prime is 13330214005429. The reversal of 13330214005331 is 13350041203331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13330214005331 is a prime.

It is a super-2 number, since 2×13330214005331² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13330214005294 and 13330214005303.

It is not an unprimeable number, because it can be changed into a prime (13330214005231) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 28605609221 + ... + 28605609686.

It is an arithmetic number, because the mean of its divisors is an integer number (3346856306118).

Almost surely, 2^{13330214005331} is an apocalyptic number.

13330214005331 is a deficient number, since it is larger than the sum of its proper divisors (57211219141).

13330214005331 is an equidigital number, since it uses as much as digits as its factorization.

13330214005331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 57211219140.

The product of its (nonzero) digits is 9720, while the sum is 29.

Adding to 13330214005331 its reverse (13350041203331), we get a palindrome (26680255208662).

The spelling of 13330214005331 in words is "thirteen trillion, three hundred thirty billion, two hundred fourteen million, five thousand, three hundred thirty-one".