1333022002121 has 4 divisors (see below), whose sum is σ = 1333031971200. Its totient is φ = 1333012033044.

The previous prime is 1333022002097. The next prime is 1333022002139. The reversal of 1333022002121 is 1212002203331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1333022002121 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1333022002093 and 1333022002102.

It is not an unprimeable number, because it can be changed into a prime (1333025002121) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4781201 + ... + 5052318.

It is an arithmetic number, because the mean of its divisors is an integer number (333257992800).

Almost surely, 2^{1333022002121} is an apocalyptic number.

It is an amenable number.

1333022002121 is a deficient number, since it is larger than the sum of its proper divisors (9969079).

1333022002121 is an equidigital number, since it uses as much as digits as its factorization.

1333022002121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9969078.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 1333022002121 its reverse (1212002203331), we get a palindrome (2545024205452).

The spelling of 1333022002121 in words is "one trillion, three hundred thirty-three billion, twenty-two million, two thousand, one hundred twenty-one".