Base | Representation |
---|---|
bin | 11110010011110110001100… |
… | …001100011011011011001011 |
3 | 122110222212011012211120112010 |
4 | 132103312030030123123023 |
5 | 114433033124010044001 |
6 | 1151303330511551003 |
7 | 40035662262352353 |
oct | 3623661414333313 |
9 | 573885135746463 |
10 | 133305252034251 |
11 | 39525492570280 |
12 | 12b4b54b22b463 |
13 | 594c829047b5b |
14 | 24cc019943b63 |
15 | 10628975d98d6 |
hex | 793d8c31b6cb |
133305252034251 has 16 divisors (see below), whose sum is σ = 195425308643328. Its totient is φ = 80154911743200.
The previous prime is 133305252034247. The next prime is 133305252034391. The reversal of 133305252034251 is 152430252503331.
It is not a de Polignac number, because 133305252034251 - 22 = 133305252034247 is a prime.
It is not an unprimeable number, because it can be changed into a prime (133305252034151) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 15903748140 + ... + 15903756521.
It is an arithmetic number, because the mean of its divisors is an integer number (12214081790208).
Almost surely, 2133305252034251 is an apocalyptic number.
133305252034251 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
133305252034251 is a deficient number, since it is larger than the sum of its proper divisors (62120056609077).
133305252034251 is a wasteful number, since it uses less digits than its factorization.
133305252034251 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 31807504802.
The product of its (nonzero) digits is 324000, while the sum is 39.
The spelling of 133305252034251 in words is "one hundred thirty-three trillion, three hundred five billion, two hundred fifty-two million, thirty-four thousand, two hundred fifty-one".
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