1333102112002 has 4 divisors (see below), whose sum is σ = 1999653168006. Its totient is φ = 666551056000.

The previous prime is 1333102111967. The next prime is 1333102112011. The reversal of 1333102112002 is 2002112013331.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 907582034241 + 425520077761 = 952671^2 + 652319^2 .

It is a super-2 number, since 2×1333102112002² (a number of 25 digits) contains 22 as substring.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 333275527999 + ... + 333275528002.

Almost surely, 2^{1333102112002} is an apocalyptic number.

1333102112002 is a deficient number, since it is larger than the sum of its proper divisors (666551056004).

1333102112002 is an equidigital number, since it uses as much as digits as its factorization.

1333102112002 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 666551056003.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 1333102112002 its reverse (2002112013331), we get a palindrome (3335214125333).

The spelling of 1333102112002 in words is "one trillion, three hundred thirty-three billion, one hundred two million, one hundred twelve thousand, two".