13331031401203 has 4 divisors (see below), whose sum is σ = 13337935096248. Its totient is φ = 13324127706160.

The previous prime is 13331031401153. The next prime is 13331031401249. The reversal of 13331031401203 is 30210413013331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13331031401203 - 2⁹ = 13331031400691 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13331031401263) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3451844626 + ... + 3451848487.

It is an arithmetic number, because the mean of its divisors is an integer number (3334483774062).

Almost surely, 2^{13331031401203} is an apocalyptic number.

13331031401203 is a deficient number, since it is larger than the sum of its proper divisors (6903695045).

13331031401203 is an equidigital number, since it uses as much as digits as its factorization.

13331031401203 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6903695044.

The product of its (nonzero) digits is 1944, while the sum is 25.

Adding to 13331031401203 its reverse (30210413013331), we get a palindrome (43541444414534).

The spelling of 13331031401203 in words is "thirteen trillion, three hundred thirty-one billion, thirty-one million, four hundred one thousand, two hundred three".