13331042241401 has 4 divisors (see below), whose sum is σ = 14032676043600. Its totient is φ = 12629408439204.

The previous prime is 13331042241317. The next prime is 13331042241449. The reversal of 13331042241401 is 10414224013331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13331042241401 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13331042243401) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 350816901071 + ... + 350816901108.

It is an arithmetic number, because the mean of its divisors is an integer number (3508169010900).

Almost surely, 2^{13331042241401} is an apocalyptic number.

It is an amenable number.

13331042241401 is a deficient number, since it is larger than the sum of its proper divisors (701633802199).

13331042241401 is an equidigital number, since it uses as much as digits as its factorization.

13331042241401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 701633802198.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 13331042241401 its reverse (10414224013331), we get a palindrome (23745266254732).

The spelling of 13331042241401 in words is "thirteen trillion, three hundred thirty-one billion, forty-two million, two hundred forty-one thousand, four hundred one".