13331111012122 has 4 divisors (see below), whose sum is σ = 19996666518186. Its totient is φ = 6665555506060.

The previous prime is 13331111012119. The next prime is 13331111012137. The reversal of 13331111012122 is 22121011113331.

13331111012122 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 13330611534321 + 499477801 = 3651111^2 + 22349^2 .

It is a junction number, because it is equal to n+sod(n) for n = 13331111012093 and 13331111012102.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3332777753029 + ... + 3332777753032.

Almost surely, 2^{13331111012122} is an apocalyptic number.

13331111012122 is a deficient number, since it is larger than the sum of its proper divisors (6665555506064).

13331111012122 is an equidigital number, since it uses as much as digits as its factorization.

13331111012122 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6665555506063.

The product of its (nonzero) digits is 216, while the sum is 22.

Adding to 13331111012122 its reverse (22121011113331), we get a palindrome (35452122125453).

The spelling of 13331111012122 in words is "thirteen trillion, three hundred thirty-one billion, one hundred eleven million, twelve thousand, one hundred twenty-two".