Base | Representation |
---|---|
bin | 111110000100111110… |
… | …1111111100001111011 |
3 | 110202002200121021011121 |
4 | 1330021331333201323 |
5 | 4141010133411443 |
6 | 141124202210111 |
7 | 12426401530216 |
oct | 1741175774173 |
9 | 422080537147 |
10 | 133311232123 |
11 | 5159a795903 |
12 | 21a057b3937 |
13 | c756bba494 |
14 | 664916a77d |
15 | 37038d44ed |
hex | 1f09f7f87b |
133311232123 has 2 divisors, whose sum is σ = 133311232124. Its totient is φ = 133311232122.
The previous prime is 133311232079. The next prime is 133311232169. The reversal of 133311232123 is 321232113331.
It is a weak prime.
It is an emirp because it is prime and its reverse (321232113331) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-133311232123 is a prime.
It is a super-2 number, since 2×1333112321232 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (133311232193) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66655616061 + 66655616062.
It is an arithmetic number, because the mean of its divisors is an integer number (66655616062).
Almost surely, 2133311232123 is an apocalyptic number.
133311232123 is a deficient number, since it is larger than the sum of its proper divisors (1).
133311232123 is an equidigital number, since it uses as much as digits as its factorization.
133311232123 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1944, while the sum is 25.
Adding to 133311232123 its reverse (321232113331), we get a palindrome (454543345454).
The spelling of 133311232123 in words is "one hundred thirty-three billion, three hundred eleven million, two hundred thirty-two thousand, one hundred twenty-three".
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