Base | Representation |
---|---|
bin | 1100000111111110010101… |
… | …0110101111111000011011 |
3 | 1202012102222110202211220211 |
4 | 3001333211112233320123 |
5 | 3221404124123341433 |
6 | 44204123125031551 |
7 | 2544066602536264 |
oct | 301774526577033 |
9 | 52172873684824 |
10 | 13331131465243 |
11 | 427a779196669 |
12 | 15b37b4b555b7 |
13 | 7591743c8977 |
14 | 34133198196b |
15 | 181b8ee6d8cd |
hex | c1fe55afe1b |
13331131465243 has 2 divisors, whose sum is σ = 13331131465244. Its totient is φ = 13331131465242.
The previous prime is 13331131465217. The next prime is 13331131465247. The reversal of 13331131465243 is 34256413113331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13331131465243 - 225 = 13331097910811 is a prime.
It is a super-2 number, since 2×133311314652432 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13331131465196 and 13331131465205.
It is not a weakly prime, because it can be changed into another prime (13331131465247) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6665565732621 + 6665565732622.
It is an arithmetic number, because the mean of its divisors is an integer number (6665565732622).
Almost surely, 213331131465243 is an apocalyptic number.
13331131465243 is a deficient number, since it is larger than the sum of its proper divisors (1).
13331131465243 is an equidigital number, since it uses as much as digits as its factorization.
13331131465243 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 233280, while the sum is 40.
Adding to 13331131465243 its reverse (34256413113331), we get a palindrome (47587544578574).
The spelling of 13331131465243 in words is "thirteen trillion, three hundred thirty-one billion, one hundred thirty-one million, four hundred sixty-five thousand, two hundred forty-three".
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