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133312030113131 is a prime number
BaseRepresentation
bin11110010011111100100000…
…001100101111110101101011
3122111000111122120222122202122
4132103330200030233311223
5114433141014202110011
61151310411241421455
740036322245154312
oct3623744014576553
9574014576878678
10133312030113131
113952835061a261
1212b5092119a88b
13595036938cb0c
1424cc49dc13279
151062b426b93db
hex793f2032fd6b

133312030113131 has 2 divisors, whose sum is σ = 133312030113132. Its totient is φ = 133312030113130.

The previous prime is 133312030113001. The next prime is 133312030113169. The reversal of 133312030113131 is 131311030213331.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-133312030113131 is a prime.

It is a super-2 number, since 2×1333120301131312 (a number of 29 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a self number, because there is not a number n which added to its sum of digits gives 133312030113131.

It is not a weakly prime, because it can be changed into another prime (133312030110131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66656015056565 + 66656015056566.

It is an arithmetic number, because the mean of its divisors is an integer number (66656015056566).

Almost surely, 2133312030113131 is an apocalyptic number.

133312030113131 is a deficient number, since it is larger than the sum of its proper divisors (1).

133312030113131 is an equidigital number, since it uses as much as digits as its factorization.

133312030113131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1458, while the sum is 26.

Adding to 133312030113131 its reverse (131311030213331), we get a palindrome (264623060326462).

The spelling of 133312030113131 in words is "one hundred thirty-three trillion, three hundred twelve billion, thirty million, one hundred thirteen thousand, one hundred thirty-one".