133312132113 has 4 divisors (see below), whose sum is σ = 177749509488. Its totient is φ = 88874754740.

The previous prime is 133312132087. The next prime is 133312132141. The reversal of 133312132113 is 311231213331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 311231213331 = 3 ⋅103743737777.

It is a cyclic number.

It is not a de Polignac number, because 133312132113 - 2¹⁰ = 133312131089 is a prime.

It is not an unprimeable number, because it can be changed into a prime (133312132153) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22218688683 + ... + 22218688688.

It is an arithmetic number, because the mean of its divisors is an integer number (44437377372).

Almost surely, 2^133312132113 is an apocalyptic number.

It is an amenable number.

133312132113 is a deficient number, since it is larger than the sum of its proper divisors (44437377375).

133312132113 is an equidigital number, since it uses as much as digits as its factorization.

133312132113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 44437377374.

The product of its digits is 972, while the sum is 24.

Adding to 133312132113 its reverse (311231213331), we get a palindrome (444543345444).

The spelling of 133312132113 in words is "one hundred thirty-three billion, three hundred twelve million, one hundred thirty-two thousand, one hundred thirteen".