1333122103113 has 4 divisors (see below), whose sum is σ = 1777496137488. Its totient is φ = 888748068740.

The previous prime is 1333122103021. The next prime is 1333122103153. The reversal of 1333122103113 is 3113012213331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1333122103113 - 2¹⁴ = 1333122086729 is a prime.

It is not an unprimeable number, because it can be changed into a prime (1333122103153) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 222187017183 + ... + 222187017188.

It is an arithmetic number, because the mean of its divisors is an integer number (444374034372).

Almost surely, 2^{1333122103113} is an apocalyptic number.

It is an amenable number.

1333122103113 is a deficient number, since it is larger than the sum of its proper divisors (444374034375).

1333122103113 is an equidigital number, since it uses as much as digits as its factorization.

1333122103113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 444374034374.

The product of its (nonzero) digits is 972, while the sum is 24.

Adding to 1333122103113 its reverse (3113012213331), we get a palindrome (4446134316444).

The spelling of 1333122103113 in words is "one trillion, three hundred thirty-three billion, one hundred twenty-two million, one hundred three thousand, one hundred thirteen".