Base | Representation |
---|---|
bin | 10011011001100100011… |
… | …001101111001000111010 |
3 | 11201110000201121202200202 |
4 | 103121210121233020322 |
5 | 133320214312030132 |
6 | 2500232345002202 |
7 | 165213030560231 |
oct | 23314431571072 |
9 | 4643021552622 |
10 | 1333124330042 |
11 | 474413a2566a |
12 | 196450783362 |
13 | 9893685582b |
14 | 48748921b18 |
15 | 24a26ea1762 |
hex | 1366466f23a |
1333124330042 has 8 divisors (see below), whose sum is σ = 2048459336532. Its totient is φ = 650304551200.
The previous prime is 1333124330033. The next prime is 1333124330107. The reversal of 1333124330042 is 2400334213331.
It can be written as a sum of positive squares in 2 ways, for example, as 1100461842841 + 232662487201 = 1049029^2 + 482351^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a super-3 number, since 3×13331243300423 (a number of 37 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1333124329987 and 1333124330014.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8128806809 + ... + 8128806972.
Almost surely, 21333124330042 is an apocalyptic number.
1333124330042 is a deficient number, since it is larger than the sum of its proper divisors (715335006490).
1333124330042 is a wasteful number, since it uses less digits than its factorization.
1333124330042 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 16257613824.
The product of its (nonzero) digits is 15552, while the sum is 29.
Adding to 1333124330042 its reverse (2400334213331), we get a palindrome (3733458543373).
The spelling of 1333124330042 in words is "one trillion, three hundred thirty-three billion, one hundred twenty-four million, three hundred thirty thousand, forty-two".
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