Base | Representation |
---|---|
bin | 11110010011111100111100… |
… | …100010011000000110100011 |
3 | 122111000112212201121002211221 |
4 | 132103330330202120012203 |
5 | 114433143002404420443 |
6 | 1151310530343515511 |
7 | 40036340110235362 |
oct | 3623747442300643 |
9 | 574015781532757 |
10 | 133312505545123 |
11 | 39528574a26363 |
12 | 12b50a34458b97 |
13 | 5950413a22518 |
14 | 24cc5070117d9 |
15 | 1062b6e2cceed |
hex | 793f3c8981a3 |
133312505545123 has 4 divisors (see below), whose sum is σ = 134606801715568. Its totient is φ = 132018209374680.
The previous prime is 133312505545117. The next prime is 133312505545127. The reversal of 133312505545123 is 321545505213331.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-133312505545123 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 133312505545123.
It is not an unprimeable number, because it can be changed into a prime (133312505545127) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 647148085068 + ... + 647148085273.
It is an arithmetic number, because the mean of its divisors is an integer number (33651700428892).
Almost surely, 2133312505545123 is an apocalyptic number.
133312505545123 is a deficient number, since it is larger than the sum of its proper divisors (1294296170445).
133312505545123 is a wasteful number, since it uses less digits than its factorization.
133312505545123 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1294296170444.
The product of its (nonzero) digits is 810000, while the sum is 43.
The spelling of 133312505545123 in words is "one hundred thirty-three trillion, three hundred twelve billion, five hundred five million, five hundred forty-five thousand, one hundred twenty-three".
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