Base | Representation |
---|---|
bin | 11110010011111101011010… |
… | …001100100000110101110111 |
3 | 122111000121011101220001022000 |
4 | 132103331122030200311313 |
5 | 114433200012300131411 |
6 | 1151311052000510343 |
7 | 40036355331524001 |
oct | 3623753214406567 |
9 | 574017141801260 |
10 | 133313003130231 |
11 | 395287aa893421 |
12 | 12b50b5301b3b3 |
13 | 5950492b40392 |
14 | 24cc553139371 |
15 | 1062b9cd1a956 |
hex | 793f5a320d77 |
133313003130231 has 32 divisors (see below), whose sum is σ = 204503319552000. Its totient is φ = 85729943152224.
The previous prime is 133313003130187. The next prime is 133313003130239. The reversal of 133313003130231 is 132031300313331.
133313003130231 is a `hidden beast` number, since 1 + 3 + 3 + 313 + 0 + 0 + 313 + 0 + 2 + 31 = 666.
It is not a de Polignac number, because 133313003130231 - 223 = 133312994741623 is a prime.
It is a super-2 number, since 2×1333130031302312 (a number of 29 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is a junction number, because it is equal to n+sod(n) for n = 133313003130195 and 133313003130204.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (133313003130239) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 79251991 + ... + 80916648.
It is an arithmetic number, because the mean of its divisors is an integer number (6390728736000).
Almost surely, 2133313003130231 is an apocalyptic number.
133313003130231 is a deficient number, since it is larger than the sum of its proper divisors (71190316421769).
133313003130231 is a wasteful number, since it uses less digits than its factorization.
133313003130231 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 160169740 (or 160169734 counting only the distinct ones).
The product of its (nonzero) digits is 4374, while the sum is 27.
Adding to 133313003130231 its reverse (132031300313331), we get a palindrome (265344303443562).
The spelling of 133313003130231 in words is "one hundred thirty-three trillion, three hundred thirteen billion, three million, one hundred thirty thousand, two hundred thirty-one".
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