Base | Representation |
---|---|
bin | 11110010011111101011010… |
… | …101011101011011101111011 |
3 | 122111000121011222021010102011 |
4 | 132103331122223223131323 |
5 | 114433200021343101334 |
6 | 1151311052451550351 |
7 | 40036355461132132 |
oct | 3623753253533573 |
9 | 574017158233364 |
10 | 133313011300219 |
11 | 39528804463683 |
12 | 12b50b558bb3b7 |
13 | 5950494740caa |
14 | 24cc554264919 |
15 | 1062b9d8d1564 |
hex | 793f5aaeb77b |
133313011300219 has 2 divisors, whose sum is σ = 133313011300220. Its totient is φ = 133313011300218.
The previous prime is 133313011300199. The next prime is 133313011300243. The reversal of 133313011300219 is 912003110313331.
It is a weak prime.
It is an emirp because it is prime and its reverse (912003110313331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 133313011300219 - 239 = 132763255486331 is a prime.
It is a super-2 number, since 2×1333130113002192 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (133313011300919) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66656505650109 + 66656505650110.
It is an arithmetic number, because the mean of its divisors is an integer number (66656505650110).
Almost surely, 2133313011300219 is an apocalyptic number.
133313011300219 is a deficient number, since it is larger than the sum of its proper divisors (1).
133313011300219 is an equidigital number, since it uses as much as digits as its factorization.
133313011300219 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4374, while the sum is 31.
The spelling of 133313011300219 in words is "one hundred thirty-three trillion, three hundred thirteen billion, eleven million, three hundred thousand, two hundred nineteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.076 sec. • engine limits •