13331310111331 has 4 divisors (see below), whose sum is σ = 13333999507072. Its totient is φ = 13328620715592.

The previous prime is 13331310111323. The next prime is 13331310111373. The reversal of 13331310111331 is 13311101313331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13331310111331 - 2³ = 13331310111323 is a prime.

It is a super-2 number, since 2×13331310111331² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13331310111296 and 13331310111305.

It is not an unprimeable number, because it can be changed into a prime (13331310111391) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1344690435 + ... + 1344700348.

It is an arithmetic number, because the mean of its divisors is an integer number (3333499876768).

Almost surely, 2^{13331310111331} is an apocalyptic number.

13331310111331 is a deficient number, since it is larger than the sum of its proper divisors (2689395741).

13331310111331 is an equidigital number, since it uses as much as digits as its factorization.

13331310111331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2689395740.

The product of its (nonzero) digits is 729, while the sum is 25.

Adding to 13331310111331 its reverse (13311101313331), we get a palindrome (26642411424662).

The spelling of 13331310111331 in words is "thirteen trillion, three hundred thirty-one billion, three hundred ten million, one hundred eleven thousand, three hundred thirty-one".