Base | Representation |
---|---|
bin | 1100000111111111000010… |
… | …1010111011010101010011 |
3 | 1202012110110200222200021211 |
4 | 3001333300222323111103 |
5 | 3221410021223220103 |
6 | 44204154030000551 |
7 | 2544104366254234 |
oct | 301776052732523 |
9 | 52173420880254 |
10 | 13331321304403 |
11 | 427a866369633 |
12 | 15b3848646157 |
13 | 7591a483612b |
14 | 34134cc7b08b |
15 | 181ba196c36d |
hex | c1ff0abb553 |
13331321304403 has 4 divisors (see below), whose sum is σ = 13343862529648. Its totient is φ = 13318780079160.
The previous prime is 13331321304317. The next prime is 13331321304421. The reversal of 13331321304403 is 30440312313331.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13331321304403 - 225 = 13331287749971 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13331321304443) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6270611028 + ... + 6270613153.
It is an arithmetic number, because the mean of its divisors is an integer number (3335965632412).
Almost surely, 213331321304403 is an apocalyptic number.
13331321304403 is a deficient number, since it is larger than the sum of its proper divisors (12541225245).
13331321304403 is a wasteful number, since it uses less digits than its factorization.
13331321304403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 12541225244.
The product of its (nonzero) digits is 23328, while the sum is 31.
Adding to 13331321304403 its reverse (30440312313331), we get a palindrome (43771633617734).
The spelling of 13331321304403 in words is "thirteen trillion, three hundred thirty-one billion, three hundred twenty-one million, three hundred four thousand, four hundred three".
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