Base | Representation |
---|---|
bin | 11110010011111101101110… |
… | …011110001101010110110011 |
3 | 122111000122001010000010210002 |
4 | 132103331232132031112303 |
5 | 114433201211342011311 |
6 | 1151311145432100215 |
7 | 40036366632163316 |
oct | 3623755636152663 |
9 | 574018033003702 |
10 | 133313343313331 |
11 | 39528964912a85 |
12 | 12b51028b3466b |
13 | 595051846a15c |
14 | 24cc5863ac97d |
15 | 1062bbcb1593b |
hex | 793f6e78d5b3 |
133313343313331 has 4 divisors (see below), whose sum is σ = 133314697630392. Its totient is φ = 133311988996272.
The previous prime is 133313343313321. The next prime is 133313343313393.
133313343313331 is nontrivially palindromic in base 10.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-133313343313331 is a prime.
It is a super-2 number, since 2×1333133433133312 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (133313343313321) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 677010866 + ... + 677207751.
It is an arithmetic number, because the mean of its divisors is an integer number (33328674407598).
Almost surely, 2133313343313331 is an apocalyptic number.
133313343313331 is a deficient number, since it is larger than the sum of its proper divisors (1354317061).
133313343313331 is an equidigital number, since it uses as much as digits as its factorization.
133313343313331 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1354317060.
The product of its digits is 236196, while the sum is 38.
The spelling of 133313343313331 in words is "one hundred thirty-three trillion, three hundred thirteen billion, three hundred forty-three million, three hundred thirteen thousand, three hundred thirty-one".
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