133314030011483 has 2 divisors, whose sum is σ = 133314030011484. Its totient is φ = 133314030011482.

The previous prime is 133314030011347. The next prime is 133314030011549. The reversal of 133314030011483 is 384110030413331.

It is a strong prime.

It is an emirp because it is prime and its reverse (384110030413331) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 133314030011483 - 2⁴² = 128915983500379 is a prime.

It is a super-2 number, since 2×133314030011483² (a number of 29 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is not a weakly prime, because it can be changed into another prime (133311030011483) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66657015005741 + 66657015005742.

It is an arithmetic number, because the mean of its divisors is an integer number (66657015005742).

Almost surely, 2^{133314030011483} is an apocalyptic number.

133314030011483 is a deficient number, since it is larger than the sum of its proper divisors (1).

133314030011483 is an equidigital number, since it uses as much as digits as its factorization.

133314030011483 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 31104, while the sum is 35.

The spelling of 133314030011483 in words is "one hundred thirty-three trillion, three hundred fourteen billion, thirty million, eleven thousand, four hundred eighty-three".