Base | Representation |
---|---|
bin | 11000110101001110… |
… | …11101110010101011 |
3 | 1021102002111002110001 |
4 | 30122213131302223 |
5 | 204300323031042 |
6 | 10042511203431 |
7 | 651236333113 |
oct | 143247356253 |
9 | 37362432401 |
10 | 13331455147 |
11 | 572129362a |
12 | 2700816577 |
13 | 1345c63bca |
14 | 9067aa043 |
15 | 5305c5bb7 |
hex | 31a9ddcab |
13331455147 has 2 divisors, whose sum is σ = 13331455148. Its totient is φ = 13331455146.
The previous prime is 13331455099. The next prime is 13331455183. The reversal of 13331455147 is 74155413331.
It is a strong prime.
It is an emirp because it is prime and its reverse (74155413331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13331455147 - 231 = 11183971499 is a prime.
It is not a weakly prime, because it can be changed into another prime (13331455187) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6665727573 + 6665727574.
It is an arithmetic number, because the mean of its divisors is an integer number (6665727574).
Almost surely, 213331455147 is an apocalyptic number.
13331455147 is a deficient number, since it is larger than the sum of its proper divisors (1).
13331455147 is an equidigital number, since it uses as much as digits as its factorization.
13331455147 is an evil number, because the sum of its binary digits is even.
The product of its digits is 75600, while the sum is 37.
Adding to 13331455147 its reverse (74155413331), we get a palindrome (87486868478).
The spelling of 13331455147 in words is "thirteen billion, three hundred thirty-one million, four hundred fifty-five thousand, one hundred forty-seven".
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