Base | Representation |
---|---|
bin | 11000110101001110… |
… | …11101111000111001 |
3 | 1021102002111002222210 |
4 | 30122213131320321 |
5 | 204300323034140 |
6 | 10042511205333 |
7 | 651236334222 |
oct | 143247357071 |
9 | 37362432883 |
10 | 13331455545 |
11 | 5721293961 |
12 | 2700816849 |
13 | 1345c64145 |
14 | 9067aa249 |
15 | 5305c5d80 |
hex | 31a9dde39 |
13331455545 has 32 divisors (see below), whose sum is σ = 22459852800. Its totient is φ = 6733831104.
The previous prime is 13331455531. The next prime is 13331455547. The reversal of 13331455545 is 54555413331.
It is not a de Polignac number, because 13331455545 - 25 = 13331455513 is a prime.
It is a super-2 number, since 2×133314555452 (a number of 21 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (13331455547) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1431474 + ... + 1440756.
It is an arithmetic number, because the mean of its divisors is an integer number (701870400).
Almost surely, 213331455545 is an apocalyptic number.
13331455545 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
13331455545 is a deficient number, since it is larger than the sum of its proper divisors (9128397255).
13331455545 is a wasteful number, since it uses less digits than its factorization.
13331455545 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 14349.
The product of its digits is 270000, while the sum is 39.
Adding to 13331455545 its reverse (54555413331), we get a palindrome (67886868876).
The spelling of 13331455545 in words is "thirteen billion, three hundred thirty-one million, four hundred fifty-five thousand, five hundred forty-five".
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