Base | Representation |
---|---|
bin | 11000110101010011… |
… | …00000101001100011 |
3 | 1021102010111022200121 |
4 | 30122221200221203 |
5 | 204300442204024 |
6 | 10042530501111 |
7 | 651244024555 |
oct | 143251405143 |
9 | 37363438617 |
10 | 13331991139 |
11 | 572161a2a5 |
12 | 2700a34797 |
13 | 13460c0b6c |
14 | 9068a94d5 |
15 | 53067e8e4 |
hex | 31aa60a63 |
13331991139 has 2 divisors, whose sum is σ = 13331991140. Its totient is φ = 13331991138.
The previous prime is 13331991097. The next prime is 13331991149. The reversal of 13331991139 is 93119913331.
It is a strong prime.
It is an emirp because it is prime and its reverse (93119913331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13331991139 - 211 = 13331989091 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13331991095 and 13331991104.
It is not a weakly prime, because it can be changed into another prime (13331991149) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6665995569 + 6665995570.
It is an arithmetic number, because the mean of its divisors is an integer number (6665995570).
Almost surely, 213331991139 is an apocalyptic number.
13331991139 is a deficient number, since it is larger than the sum of its proper divisors (1).
13331991139 is an equidigital number, since it uses as much as digits as its factorization.
13331991139 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 59049, while the sum is 43.
The spelling of 13331991139 in words is "thirteen billion, three hundred thirty-one million, nine hundred ninety-one thousand, one hundred thirty-nine".
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