Base | Representation |
---|---|
bin | 111110000101001111… |
… | …1011100111100000011 |
3 | 110202010022002220000011 |
4 | 1330022133130330003 |
5 | 4141014410101311 |
6 | 141125114205351 |
7 | 12426536221234 |
oct | 1741237347403 |
9 | 422108086004 |
10 | 133320003331 |
11 | 515a4736839 |
12 | 21a08723857 |
13 | c75896b948 |
14 | 664a3b108b |
15 | 3704568321 |
hex | 1f0a7dcf03 |
133320003331 has 2 divisors, whose sum is σ = 133320003332. Its totient is φ = 133320003330.
The previous prime is 133320003269. The next prime is 133320003347. The reversal of 133320003331 is 133300023331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 133320003331 - 231 = 131172519683 is a prime.
It is a super-4 number, since 4×1333200033314 (a number of 46 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (133320003361) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66660001665 + 66660001666.
It is an arithmetic number, because the mean of its divisors is an integer number (66660001666).
Almost surely, 2133320003331 is an apocalyptic number.
133320003331 is a deficient number, since it is larger than the sum of its proper divisors (1).
133320003331 is an equidigital number, since it uses as much as digits as its factorization.
133320003331 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1458, while the sum is 22.
Adding to 133320003331 its reverse (133300023331), we get a palindrome (266620026662).
The spelling of 133320003331 in words is "one hundred thirty-three billion, three hundred twenty million, three thousand, three hundred thirty-one".
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