13332011310313 has 2 divisors, whose sum is σ = 13332011310314. Its totient is φ = 13332011310312.

The previous prime is 13332011310271. The next prime is 13332011310323. The reversal of 13332011310313 is 31301311023331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11911941071424 + 1420070238889 = 3451368^2 + 1191667^2 .

It is an emirp because it is prime and its reverse (31301311023331) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13332011310313 - 2¹³ = 13332011302121 is a prime.

It is not a weakly prime, because it can be changed into another prime (13332011310323) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6666005655156 + 6666005655157.

It is an arithmetic number, because the mean of its divisors is an integer number (6666005655157).

Almost surely, 2^{13332011310313} is an apocalyptic number.

It is an amenable number.

13332011310313 is a deficient number, since it is larger than the sum of its proper divisors (1).

13332011310313 is an equidigital number, since it uses as much as digits as its factorization.

13332011310313 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1458, while the sum is 25.

Adding to 13332011310313 its reverse (31301311023331), we get a palindrome (44633322333644).

The spelling of 13332011310313 in words is "thirteen trillion, three hundred thirty-two billion, eleven million, three hundred ten thousand, three hundred thirteen".