Base | Representation |
---|---|
bin | 1100001000000001101001… |
… | …1100010000000011001011 |
3 | 1202012112021112122210100122 |
4 | 3002000122130100003023 |
5 | 3221412440124201141 |
6 | 44204351342253455 |
7 | 2544130636031465 |
oct | 302003234200313 |
9 | 52175245583318 |
10 | 13332022100171 |
11 | 4280095a01895 |
12 | 15b3a0328728b |
13 | 759286a93798 |
14 | 3413b7d81135 |
15 | 181be324a64b |
hex | c201a7100cb |
13332022100171 has 2 divisors, whose sum is σ = 13332022100172. Its totient is φ = 13332022100170.
The previous prime is 13332022100083. The next prime is 13332022100179. The reversal of 13332022100171 is 17100122023331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13332022100171 - 226 = 13331954991307 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13332022100171.
It is not a weakly prime, because it can be changed into another prime (13332022100179) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6666011050085 + 6666011050086.
It is an arithmetic number, because the mean of its divisors is an integer number (6666011050086).
Almost surely, 213332022100171 is an apocalyptic number.
13332022100171 is a deficient number, since it is larger than the sum of its proper divisors (1).
13332022100171 is an equidigital number, since it uses as much as digits as its factorization.
13332022100171 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1512, while the sum is 26.
The spelling of 13332022100171 in words is "thirteen trillion, three hundred thirty-two billion, twenty-two million, one hundred thousand, one hundred seventy-one".
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