Base | Representation |
---|---|
bin | 10011011001101001100… |
… | …000100101110111001011 |
3 | 11201110020200211220210111 |
4 | 103121221200211313023 |
5 | 133320403230410011 |
6 | 2500245045255151 |
7 | 165215121063163 |
oct | 23315140456713 |
9 | 4643220756714 |
10 | 1333210013131 |
11 | 474458328637 |
12 | 1964754044b7 |
13 | 9894b525899 |
14 | 487560675a3 |
15 | 24a2e779121 |
hex | 13669825dcb |
1333210013131 has 4 divisors (see below), whose sum is σ = 1333821860200. Its totient is φ = 1332598166064.
The previous prime is 1333210013053. The next prime is 1333210013147. The reversal of 1333210013131 is 1313100123331.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1333210013131 is a prime.
It is a super-2 number, since 2×13332100131312 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1333210013231) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 305920266 + ... + 305924623.
It is an arithmetic number, because the mean of its divisors is an integer number (333455465050).
Almost surely, 21333210013131 is an apocalyptic number.
1333210013131 is a deficient number, since it is larger than the sum of its proper divisors (611847069).
1333210013131 is an equidigital number, since it uses as much as digits as its factorization.
1333210013131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 611847068.
The product of its (nonzero) digits is 486, while the sum is 22.
Adding to 1333210013131 its reverse (1313100123331), we get a palindrome (2646310136462).
The spelling of 1333210013131 in words is "one trillion, three hundred thirty-three billion, two hundred ten million, thirteen thousand, one hundred thirty-one".
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