Base | Representation |
---|---|
bin | 11110010100000101000101… |
… | …011001011001001111000011 |
3 | 122111001101102201202201000102 |
4 | 132110011011121121033003 |
5 | 114433313401443320003 |
6 | 1151314533425513015 |
7 | 40040066500011152 |
oct | 3624050531311703 |
9 | 574041381681012 |
10 | 133321244120003 |
11 | 3953124969aa75 |
12 | 12b52672aa276b |
13 | 59511a728c9a4 |
14 | 24ccad5815599 |
15 | 1062ed156a588 |
hex | 7941456593c3 |
133321244120003 has 4 divisors (see below), whose sum is σ = 133322920542648. Its totient is φ = 133319567697360.
The previous prime is 133321244119949. The next prime is 133321244120023. The reversal of 133321244120003 is 300021442123331.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 133321244120003 - 212 = 133321244115907 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (133321244120023) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 838092026 + ... + 838251087.
It is an arithmetic number, because the mean of its divisors is an integer number (33330730135662).
Almost surely, 2133321244120003 is an apocalyptic number.
133321244120003 is a deficient number, since it is larger than the sum of its proper divisors (1676422645).
133321244120003 is an equidigital number, since it uses as much as digits as its factorization.
133321244120003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1676422644.
The product of its (nonzero) digits is 10368, while the sum is 29.
Adding to 133321244120003 its reverse (300021442123331), we get a palindrome (433342686243334).
The spelling of 133321244120003 in words is "one hundred thirty-three trillion, three hundred twenty-one billion, two hundred forty-four million, one hundred twenty thousand, three".
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