Base | Representation |
---|---|
bin | 11110010100000110101111… |
… | …010000010010111111111001 |
3 | 122111001120000111121212002012 |
4 | 132110012233100102333321 |
5 | 114433331021122320212 |
6 | 1151315425551415305 |
7 | 40040161503526655 |
oct | 3624065720227771 |
9 | 574046014555065 |
10 | 133323020120057 |
11 | 39531a80152109 |
12 | 12b52a89824535 |
13 | 59513cb1c8ab1 |
14 | 24ccc23641a65 |
15 | 1063087432922 |
hex | 7941af412ff9 |
133323020120057 has 2 divisors, whose sum is σ = 133323020120058. Its totient is φ = 133323020120056.
The previous prime is 133323020119979. The next prime is 133323020120093. The reversal of 133323020120057 is 750021020323331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 84919984761616 + 48403035358441 = 9215204^2 + 6957229^2 .
It is a cyclic number.
It is not a de Polignac number, because 133323020120057 - 218 = 133323019857913 is a prime.
It is not a weakly prime, because it can be changed into another prime (133323025120057) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66661510060028 + 66661510060029.
It is an arithmetic number, because the mean of its divisors is an integer number (66661510060029).
Almost surely, 2133323020120057 is an apocalyptic number.
It is an amenable number.
133323020120057 is a deficient number, since it is larger than the sum of its proper divisors (1).
133323020120057 is an equidigital number, since it uses as much as digits as its factorization.
133323020120057 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 22680, while the sum is 32.
Adding to 133323020120057 its reverse (750021020323331), we get a palindrome (883344040443388).
The spelling of 133323020120057 in words is "one hundred thirty-three trillion, three hundred twenty-three billion, twenty million, one hundred twenty thousand, fifty-seven".
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