133323240004153 has 2 divisors, whose sum is σ = 133323240004154. Its totient is φ = 133323240004152.

The previous prime is 133323240004121. The next prime is 133323240004183. The reversal of 133323240004153 is 351400042323331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 132615307920384 + 707932083769 = 11515872^2 + 841387^2 .

It is a cyclic number.

It is not a de Polignac number, because 133323240004153 - 2⁵ = 133323240004121 is a prime.

It is not a weakly prime, because it can be changed into another prime (133323240004183) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66661620002076 + 66661620002077.

It is an arithmetic number, because the mean of its divisors is an integer number (66661620002077).

Almost surely, 2^{133323240004153} is an apocalyptic number.

It is an amenable number.

133323240004153 is a deficient number, since it is larger than the sum of its proper divisors (1).

133323240004153 is an equidigital number, since it uses as much as digits as its factorization.

133323240004153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 77760, while the sum is 34.

Adding to 133323240004153 its reverse (351400042323331), we get a palindrome (484723282327484).

The spelling of 133323240004153 in words is "one hundred thirty-three trillion, three hundred twenty-three billion, two hundred forty million, four thousand, one hundred fifty-three".