Base | Representation |
---|---|
bin | 11110010100001101010000… |
… | …100011110010110010000001 |
3 | 122111002020002102122011122222 |
4 | 132110031100203302302001 |
5 | 114433434340430030144 |
6 | 1151322544411540425 |
7 | 40040530136035625 |
oct | 3624152043626201 |
9 | 574066072564588 |
10 | 133330021330049 |
11 | 39534a43152875 |
12 | 12b5430245a715 |
13 | 5951c758366bb |
14 | 24cd2c93d5185 |
15 | 1063346dda2ee |
hex | 7943508f2c81 |
133330021330049 has 2 divisors, whose sum is σ = 133330021330050. Its totient is φ = 133330021330048.
The previous prime is 133330021329997. The next prime is 133330021330069. The reversal of 133330021330049 is 940033120033331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 132343511524225 + 986509805824 = 11504065^2 + 993232^2 .
It is a cyclic number.
It is not a de Polignac number, because 133330021330049 - 216 = 133330021264513 is a prime.
It is not a weakly prime, because it can be changed into another prime (133330021330069) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66665010665024 + 66665010665025.
It is an arithmetic number, because the mean of its divisors is an integer number (66665010665025).
Almost surely, 2133330021330049 is an apocalyptic number.
It is an amenable number.
133330021330049 is a deficient number, since it is larger than the sum of its proper divisors (1).
133330021330049 is an equidigital number, since it uses as much as digits as its factorization.
133330021330049 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 52488, while the sum is 35.
The spelling of 133330021330049 in words is "one hundred thirty-three trillion, three hundred thirty billion, twenty-one million, three hundred thirty thousand, forty-nine".
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