Search a number
-
+
133333213200289 is a prime number
BaseRepresentation
bin11110010100010000001110…
…110011110011111110100001
3122111002112022212200222111021
4132110100032303303332201
5114434012410034402124
61151324233232445441
740041002214346024
oct3624201663637641
9574075285628437
10133333213200289
1139536330953163
1212b54a533a9881
135952363bb9a0b
1424cd50d2a51bb
15106348222e7e4
hex79440ecf3fa1

133333213200289 has 2 divisors, whose sum is σ = 133333213200290. Its totient is φ = 133333213200288.

The previous prime is 133333213200259. The next prime is 133333213200349. The reversal of 133333213200289 is 982002312333331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 73112897169664 + 60220316030625 = 8550608^2 + 7760175^2 .

It is an emirp because it is prime and its reverse (982002312333331) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 133333213200289 - 233 = 133324623265697 is a prime.

It is not a weakly prime, because it can be changed into another prime (133333213200259) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66666606600144 + 66666606600145.

It is an arithmetic number, because the mean of its divisors is an integer number (66666606600145).

Almost surely, 2133333213200289 is an apocalyptic number.

It is an amenable number.

133333213200289 is a deficient number, since it is larger than the sum of its proper divisors (1).

133333213200289 is an equidigital number, since it uses as much as digits as its factorization.

133333213200289 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 419904, while the sum is 43.

The spelling of 133333213200289 in words is "one hundred thirty-three trillion, three hundred thirty-three billion, two hundred thirteen million, two hundred thousand, two hundred eighty-nine".