Base | Representation |
---|---|
bin | 10011011001110110000… |
… | …001101101111001110001 |
3 | 11201110210100000112201221 |
4 | 103121312001231321301 |
5 | 133321321011222114 |
6 | 2500321550425041 |
7 | 165223251122065 |
oct | 23316601557161 |
9 | 4643710015657 |
10 | 1333420023409 |
11 | 474555928451 |
12 | 196513802181 |
13 | 98982ba6316 |
14 | 48775cd3aa5 |
15 | 24a42e0e524 |
hex | 1367606de71 |
1333420023409 has 2 divisors, whose sum is σ = 1333420023410. Its totient is φ = 1333420023408.
The previous prime is 1333420023391. The next prime is 1333420023449. The reversal of 1333420023409 is 9043200243331.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 679338608400 + 654081415009 = 824220^2 + 808753^2 .
It is an emirp because it is prime and its reverse (9043200243331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1333420023409 - 29 = 1333420022897 is a prime.
It is not a weakly prime, because it can be changed into another prime (1333420023449) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 666710011704 + 666710011705.
It is an arithmetic number, because the mean of its divisors is an integer number (666710011705).
Almost surely, 21333420023409 is an apocalyptic number.
It is an amenable number.
1333420023409 is a deficient number, since it is larger than the sum of its proper divisors (1).
1333420023409 is an equidigital number, since it uses as much as digits as its factorization.
1333420023409 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 46656, while the sum is 34.
The spelling of 1333420023409 in words is "one trillion, three hundred thirty-three billion, four hundred twenty million, twenty-three thousand, four hundred nine".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •