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13335201103481 is a prime number
BaseRepresentation
bin1100001000001101011111…
…1011001011111001111001
31202012211111002111220001222
43002003113323023321321
53221440442440302411
644210035023321425
72544302500101635
oct302032773137171
952184432456058
1013335201103481
114281477414054
1215b454ba50275
1375967259032a
143415da261dc5
15181d2c39c4db
hexc20d7ecbe79

13335201103481 has 2 divisors, whose sum is σ = 13335201103482. Its totient is φ = 13335201103480.

The previous prime is 13335201103409. The next prime is 13335201103489. The reversal of 13335201103481 is 18430110253331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9941282880400 + 3393918223081 = 3152980^2 + 1842259^2 .

It is a cyclic number.

It is not a de Polignac number, because 13335201103481 - 214 = 13335201087097 is a prime.

It is a super-2 number, since 2×133352011034812 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13335201103489) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6667600551740 + 6667600551741.

It is an arithmetic number, because the mean of its divisors is an integer number (6667600551741).

Almost surely, 213335201103481 is an apocalyptic number.

It is an amenable number.

13335201103481 is a deficient number, since it is larger than the sum of its proper divisors (1).

13335201103481 is an equidigital number, since it uses as much as digits as its factorization.

13335201103481 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 25920, while the sum is 35.

The spelling of 13335201103481 in words is "thirteen trillion, three hundred thirty-five billion, two hundred one million, one hundred three thousand, four hundred eighty-one".