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13335335142002 = 26667667571001
BaseRepresentation
bin1100001000001101111111…
…1010100000001001110010
31202012211211102201202100122
43002003133322200021302
53221441231244021002
644210100212250242
72544306015312536
oct302033772401162
952184742652318
1013335335142002
114281536044195
1215b4588910982
13759694291073
1434160dd93bc6
15181d390276a2
hexc20dfea0272

13335335142002 has 4 divisors (see below), whose sum is σ = 20003002713006. Its totient is φ = 6667667571000.

The previous prime is 13335335141993. The next prime is 13335335142029. The reversal of 13335335142002 is 20024153353331.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 9124380794281 + 4210954347721 = 3020659^2 + 2052061^2 .

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3333833785499 + ... + 3333833785502.

Almost surely, 213335335142002 is an apocalyptic number.

13335335142002 is a deficient number, since it is larger than the sum of its proper divisors (6667667571004).

13335335142002 is an equidigital number, since it uses as much as digits as its factorization.

13335335142002 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6667667571003.

The product of its (nonzero) digits is 97200, while the sum is 35.

Adding to 13335335142002 its reverse (20024153353331), we get a palindrome (33359488495333).

The spelling of 13335335142002 in words is "thirteen trillion, three hundred thirty-five billion, three hundred thirty-five million, one hundred forty-two thousand, two".

Divisors: 1 2 6667667571001 13335335142002