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133355077553 is a prime number
BaseRepresentation
bin111110000110010010…
…1001111111110110001
3110202012202002211210102
41330030211033332301
54141102344440203
6141132410042145
712430443312365
oct1741445177661
9422182084712
10133355077553
11516125125a5
1221a18419355
13c762ccc419
146650d012a5
153707695888
hex1f0c94ffb1

133355077553 has 2 divisors, whose sum is σ = 133355077554. Its totient is φ = 133355077552.

The previous prime is 133355077519. The next prime is 133355077679. The reversal of 133355077553 is 355770553331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 77182285489 + 56172792064 = 277817^2 + 237008^2 .

It is an emirp because it is prime and its reverse (355770553331) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 133355077553 - 210 = 133355076529 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 133355077498 and 133355077507.

It is not a weakly prime, because it can be changed into another prime (133355077153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66677538776 + 66677538777.

It is an arithmetic number, because the mean of its divisors is an integer number (66677538777).

Almost surely, 2133355077553 is an apocalyptic number.

It is an amenable number.

133355077553 is a deficient number, since it is larger than the sum of its proper divisors (1).

133355077553 is an equidigital number, since it uses as much as digits as its factorization.

133355077553 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2480625, while the sum is 47.

The spelling of 133355077553 in words is "one hundred thirty-three billion, three hundred fifty-five million, seventy-seven thousand, five hundred fifty-three".