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133359811024553 is a prime number
BaseRepresentation
bin11110010100101001000000…
…001010011101011010101001
3122111012001222112012110010122
4132110221000022131122221
5114434431343110241203
61151344352412253025
740042633303206131
oct3624510012353251
9574161875173118
10133359811024553
113954663a705203
1212b5a036a71175
135954a12476879
1424d0913937ac1
151063edc321538
hex794a4029d6a9

133359811024553 has 2 divisors, whose sum is σ = 133359811024554. Its totient is φ = 133359811024552.

The previous prime is 133359811024519. The next prime is 133359811024571. The reversal of 133359811024553 is 355420118953331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 84220944776809 + 49138866247744 = 9177197^2 + 7009912^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-133359811024553 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 133359811024495 and 133359811024504.

It is not a weakly prime, because it can be changed into another prime (133359861024553) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66679905512276 + 66679905512277.

It is an arithmetic number, because the mean of its divisors is an integer number (66679905512277).

Almost surely, 2133359811024553 is an apocalyptic number.

It is an amenable number.

133359811024553 is a deficient number, since it is larger than the sum of its proper divisors (1).

133359811024553 is an equidigital number, since it uses as much as digits as its factorization.

133359811024553 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5832000, while the sum is 53.

Adding to 133359811024553 its reverse (355420118953331), we get a palindrome (488779929977884).

The spelling of 133359811024553 in words is "one hundred thirty-three trillion, three hundred fifty-nine billion, eight hundred eleven million, twenty-four thousand, five hundred fifty-three".