Search a number
-
+
13338705041 = 52125602121
BaseRepresentation
bin11000110110000110…
…00111110010010001
31021102121010102102122
430123003013302101
5204304202030131
610043330424025
7651355056614
oct143303076221
937377112378
1013338705041
115725395582
122703132015
131347601a9c
1490773617b
15531058d7b
hex31b0c7c91

13338705041 has 4 divisors (see below), whose sum is σ = 13364307684. Its totient is φ = 13313102400.

The previous prime is 13338705007. The next prime is 13338705047. The reversal of 13338705041 is 14050783331.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 5491402816 + 7847302225 = 74104^2 + 88585^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13338705041 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 13338704992 and 13338705010.

It is not an unprimeable number, because it can be changed into a prime (13338705047) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12800540 + ... + 12801581.

It is an arithmetic number, because the mean of its divisors is an integer number (3341076921).

Almost surely, 213338705041 is an apocalyptic number.

It is an amenable number.

13338705041 is a deficient number, since it is larger than the sum of its proper divisors (25602643).

13338705041 is an equidigital number, since it uses as much as digits as its factorization.

13338705041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 25602642.

The product of its (nonzero) digits is 30240, while the sum is 35.

The spelling of 13338705041 in words is "thirteen billion, three hundred thirty-eight million, seven hundred five thousand, forty-one".

Divisors: 1 521 25602121 13338705041