Base | Representation |
---|---|
bin | 1100001000011111110000… |
… | …1010010011001000101011 |
3 | 1202020022010210012110121122 |
4 | 3002013330022103020223 |
5 | 3222031013111343311 |
6 | 44212205325525455 |
7 | 2544535133120555 |
oct | 302077412231053 |
9 | 52208123173548 |
10 | 13340104012331 |
11 | 4283562a37038 |
12 | 15b5499a1388b |
13 | 759c74286425 |
14 | 34194348c4d5 |
15 | 182017a260db |
hex | c21fc29322b |
13340104012331 has 2 divisors, whose sum is σ = 13340104012332. Its totient is φ = 13340104012330.
The previous prime is 13340104012327. The next prime is 13340104012343. The reversal of 13340104012331 is 13321040104331.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13340104012331 - 22 = 13340104012327 is a prime.
It is a super-2 number, since 2×133401040123312 (a number of 27 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 13340104012331.
It is not a weakly prime, because it can be changed into another prime (13340104012381) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6670052006165 + 6670052006166.
It is an arithmetic number, because the mean of its divisors is an integer number (6670052006166).
Almost surely, 213340104012331 is an apocalyptic number.
13340104012331 is a deficient number, since it is larger than the sum of its proper divisors (1).
13340104012331 is an equidigital number, since it uses as much as digits as its factorization.
13340104012331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2592, while the sum is 26.
Adding to 13340104012331 its reverse (13321040104331), we get a palindrome (26661144116662).
The spelling of 13340104012331 in words is "thirteen trillion, three hundred forty billion, one hundred four million, twelve thousand, three hundred thirty-one".
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