133402120452233 has 4 divisors (see below), whose sum is σ = 133402146170388. Its totient is φ = 133402094734080.

The previous prime is 133402120452197. The next prime is 133402120452241. The reversal of 133402120452233 is 332254021204331.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 108936751174729 + 24465369277504 = 10437277^2 + 4946248^2 .

It is a cyclic number.

It is not a de Polignac number, because 133402120452233 - 2²⁶ = 133402053343369 is a prime.

It is a super-2 number, since 2×133402120452233² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 133402120452193 and 133402120452202.

It is not an unprimeable number, because it can be changed into a prime (133402120451233) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2049608 + ... + 16462233.

It is an arithmetic number, because the mean of its divisors is an integer number (33350536542597).

Almost surely, 2^{133402120452233} is an apocalyptic number.

It is an amenable number.

133402120452233 is a deficient number, since it is larger than the sum of its proper divisors (25718155).

133402120452233 is an equidigital number, since it uses as much as digits as its factorization.

133402120452233 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 25718154.

The product of its (nonzero) digits is 103680, while the sum is 35.

Adding to 133402120452233 its reverse (332254021204331), we get a palindrome (465656141656564).

The spelling of 133402120452233 in words is "one hundred thirty-three trillion, four hundred two billion, one hundred twenty million, four hundred fifty-two thousand, two hundred thirty-three".